Base | Representation |
---|---|
bin | 1011110111001010110101… |
… | …1010110101101101011011 |
3 | 1201011211210101102020222210 |
4 | 2331302231122311231123 |
5 | 3202141344113023023 |
6 | 43423335411050203 |
7 | 2514166402366311 |
oct | 275625532655533 |
9 | 51154711366883 |
10 | 13042430204763 |
11 | 4179299920623 |
12 | 15678635a0963 |
13 | 737b8537085b |
14 | 3313852760b1 |
15 | 1793e46ae593 |
hex | bdcad6b5b5b |
13042430204763 has 16 divisors (see below), whose sum is σ = 17454741239936. Its totient is φ = 8662562910720.
The previous prime is 13042430204759. The next prime is 13042430204789. The reversal of 13042430204763 is 36740203424031.
It is not a de Polignac number, because 13042430204763 - 22 = 13042430204759 is a prime.
It is a super-2 number, since 2×130424302047632 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13042430204723) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1360006 + ... + 5285307.
It is an arithmetic number, because the mean of its divisors is an integer number (1090921327496).
Almost surely, 213042430204763 is an apocalyptic number.
13042430204763 is a deficient number, since it is larger than the sum of its proper divisors (4412311035173).
13042430204763 is a wasteful number, since it uses less digits than its factorization.
13042430204763 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6647754.
The product of its (nonzero) digits is 290304, while the sum is 39.
Adding to 13042430204763 its reverse (36740203424031), we get a palindrome (49782633628794).
The spelling of 13042430204763 in words is "thirteen trillion, forty-two billion, four hundred thirty million, two hundred four thousand, seven hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •