Base | Representation |
---|---|
bin | 11101101010001001101110… |
… | …100010000011011000101001 |
3 | 122002211221110122201012211110 |
4 | 131222021232202003120221 |
5 | 114044112120331400131 |
6 | 1141231151445020533 |
7 | 36321660035201454 |
oct | 3552115642033051 |
9 | 562757418635743 |
10 | 130440011200041 |
11 | 386203308383a4 |
12 | 127681939b4749 |
13 | 57a259539790a |
14 | 242d48a20649b |
15 | 101309d93c646 |
hex | 76a26e883629 |
130440011200041 has 16 divisors (see below), whose sum is σ = 176331452774400. Its totient is φ = 85756912529808.
The previous prime is 130440011200007. The next prime is 130440011200091. The reversal of 130440011200041 is 140002110044031.
It is not a de Polignac number, because 130440011200041 - 225 = 130439977645609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130440011199990 and 130440011200017.
It is not an unprimeable number, because it can be changed into a prime (130440011200091) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 327798651 + ... + 328196336.
It is an arithmetic number, because the mean of its divisors is an integer number (11020715798400).
Almost surely, 2130440011200041 is an apocalyptic number.
It is an amenable number.
130440011200041 is a deficient number, since it is larger than the sum of its proper divisors (45891441574359).
130440011200041 is an equidigital number, since it uses as much as digits as its factorization.
130440011200041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 655995908.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 130440011200041 its reverse (140002110044031), we get a palindrome (270442121244072).
The spelling of 130440011200041 in words is "one hundred thirty trillion, four hundred forty billion, eleven million, two hundred thousand, forty-one".
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