Base | Representation |
---|---|
bin | 1011110111010000101110… |
… | …1100111111110100000001 |
3 | 1201011222212121212221201221 |
4 | 2331310023230333310001 |
5 | 3202203114034214131 |
6 | 43424200354555041 |
7 | 2514253530542356 |
oct | 275641354776401 |
9 | 51158777787657 |
10 | 13044012023041 |
11 | 4179a3080405a |
12 | 1568025298a81 |
13 | 738077cab9bc |
14 | 33149539662d |
15 | 1794884bb411 |
hex | bdd0bb3fd01 |
13044012023041 has 16 divisors (see below), whose sum is σ = 13712821081344. Its totient is φ = 12396472717824.
The previous prime is 13044012023017. The next prime is 13044012023173. The reversal of 13044012023041 is 14032021044031.
It is a cyclic number.
It is not a de Polignac number, because 13044012023041 - 211 = 13044012020993 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13044012022997 and 13044012023015.
It is not an unprimeable number, because it can be changed into a prime (13044012023641) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26750415 + ... + 27233668.
It is an arithmetic number, because the mean of its divisors is an integer number (857051317584).
Almost surely, 213044012023041 is an apocalyptic number.
It is an amenable number.
13044012023041 is a deficient number, since it is larger than the sum of its proper divisors (668809058303).
13044012023041 is an equidigital number, since it uses as much as digits as its factorization.
13044012023041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53984280.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13044012023041 its reverse (14032021044031), we get a palindrome (27076033067072).
The spelling of 13044012023041 in words is "thirteen trillion, forty-four billion, twelve million, twenty-three thousand, forty-one".
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