Base | Representation |
---|---|
bin | 111100101111011011… |
… | …1111010100000100001 |
3 | 110110200122020220001012 |
4 | 1321132313322200201 |
5 | 4114120312003003 |
6 | 135531301350305 |
7 | 12265304644220 |
oct | 1713667724041 |
9 | 413618226035 |
10 | 130440734753 |
11 | 5035743772a |
12 | 21344408395 |
13 | c3ba2a9224 |
14 | 6455c34cb7 |
15 | 35d68c18d8 |
hex | 1e5edfa821 |
130440734753 has 16 divisors (see below), whose sum is σ = 149645905920. Its totient is φ = 111378578496.
The previous prime is 130440734663. The next prime is 130440734797. The reversal of 130440734753 is 357437044031.
It is a cyclic number.
It is not a de Polignac number, because 130440734753 - 28 = 130440734497 is a prime.
It is a super-3 number, since 3×1304407347533 (a number of 34 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130440734753.
It is not an unprimeable number, because it can be changed into a prime (130440736753) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5499203 + ... + 5522871.
It is an arithmetic number, because the mean of its divisors is an integer number (9352869120).
Almost surely, 2130440734753 is an apocalyptic number.
It is an amenable number.
130440734753 is a deficient number, since it is larger than the sum of its proper divisors (19205171167).
130440734753 is a wasteful number, since it uses less digits than its factorization.
130440734753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26656.
The product of its (nonzero) digits is 423360, while the sum is 41.
Adding to 130440734753 its reverse (357437044031), we get a palindrome (487877778784).
The spelling of 130440734753 in words is "one hundred thirty billion, four hundred forty million, seven hundred thirty-four thousand, seven hundred fifty-three".
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