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1304443918347 = 31937481301153
BaseRepresentation
bin10010111110110110111…
…010101001100000001011
311121200222221100220011120
4102332312322221200023
5132333000120341342
62435130412130323
7163146223234503
oct22766672514013
94550887326146
101304443918347
11463236648889
121909877669a3
139601599661b
14471c7856a03
1523de9136aec
hex12fb6ea980b

1304443918347 has 16 divisors (see below), whose sum is σ = 1748509760928. Its totient is φ = 865004912640.

The previous prime is 1304443918331. The next prime is 1304443918357. The reversal of 1304443918347 is 7438193444031.

It is not a de Polignac number, because 1304443918347 - 24 = 1304443918331 is a prime.

It is a super-2 number, since 2×13044439183472 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1304443918347.

It is not an unprimeable number, because it can be changed into a prime (1304443918357) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4180923 + ... + 4482075.

It is an arithmetic number, because the mean of its divisors is an integer number (109281860058).

Almost surely, 21304443918347 is an apocalyptic number.

1304443918347 is a deficient number, since it is larger than the sum of its proper divisors (444065842581).

1304443918347 is a wasteful number, since it uses less digits than its factorization.

1304443918347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 308830.

The product of its (nonzero) digits is 3483648, while the sum is 51.

The spelling of 1304443918347 in words is "one trillion, three hundred four billion, four hundred forty-three million, nine hundred eighteen thousand, three hundred forty-seven".

Divisors: 1 3 193 579 7481 22443 301153 903459 1443833 4331499 58122529 174367587 2252925593 6758776779 434814639449 1304443918347