1304623532241 has 20 divisors (see below), whose sum is σ = 1949141144500. Its totient is φ = 869633400096.

The previous prime is 1304623532231. The next prime is 1304623532299. The reversal of 1304623532241 is 1422353264031.

1304623532241 is a `hidden beast` number, since 1 + 3 + 0 + 4 + 62 + 353 + 2 + 241 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 964039241025 + 340584291216 = 981855^2 + 583596^2 .

It is not a de Polignac number, because 1304623532241 - 2¹¹ = 1304623530193 is a prime.

It is a super-3 number, since 3×1304623532241³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1304623532196 and 1304623532205.

It is not an unprimeable number, because it can be changed into a prime (1304623532231) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 455326 + ... + 1678263.

It is an arithmetic number, because the mean of its divisors is an integer number (97457057225).

Almost surely, 2^{1304623532241} is an apocalyptic number.

It is an amenable number.

1304623532241 is a deficient number, since it is larger than the sum of its proper divisors (644517612259).

1304623532241 is an equidigital number, since it uses as much as digits as its factorization.

1304623532241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2141150 (or 2141141 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 36.

Adding to 1304623532241 its reverse (1422353264031), we get a palindrome (2726976796272).

The spelling of 1304623532241 in words is "one trillion, three hundred four billion, six hundred twenty-three million, five hundred thirty-two thousand, two hundred forty-one".