Base | Representation |
---|---|
bin | 10010111111111100000… |
… | …100010000011111010010 |
3 | 11121210222210101110111210 |
4 | 102333330010100133102 |
5 | 132342334120041414 |
6 | 2435441454120550 |
7 | 163220041306110 |
oct | 22777404203722 |
9 | 4553883343453 |
10 | 1305604065234 |
11 | 463781504367 |
12 | 1910501b0156 |
13 | 9616c146081 |
14 | 47297970ab0 |
15 | 23e65dede59 |
hex | 12ffc1107d2 |
1305604065234 has 64 divisors (see below), whose sum is σ = 3062146222080. Its totient is φ = 363339527040.
The previous prime is 1305604065217. The next prime is 1305604065247. The reversal of 1305604065234 is 4325604065031.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1305604065192 and 1305604065201.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 358507 + ... + 1655214.
It is an arithmetic number, because the mean of its divisors is an integer number (47846034720).
Almost surely, 21305604065234 is an apocalyptic number.
1305604065234 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1305604065234 is an abundant number, since it is smaller than the sum of its proper divisors (1756542156846).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305604065234 is a wasteful number, since it uses less digits than its factorization.
1305604065234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2014135.
The product of its (nonzero) digits is 259200, while the sum is 39.
The spelling of 1305604065234 in words is "one trillion, three hundred five billion, six hundred four million, sixty-five thousand, two hundred thirty-four".
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