Base | Representation |
---|---|
bin | 11101101100111101101000… |
… | …000011101111000111010010 |
3 | 122010112102001122120202001120 |
4 | 131230331220003233013102 |
5 | 114110243221041231324 |
6 | 1141500015211343110 |
7 | 36341635611666654 |
oct | 3554755003570722 |
9 | 563472048522046 |
10 | 130633176117714 |
11 | 38695245356026 |
12 | 12799702451a96 |
13 | 57b786a603a7a |
14 | 243897261a6d4 |
15 | 1018106cc2179 |
hex | 76cf680ef1d2 |
130633176117714 has 16 divisors (see below), whose sum is σ = 262709812747200. Its totient is φ = 43303815287280.
The previous prime is 130633176117713. The next prime is 130633176117733. The reversal of 130633176117714 is 417711671336031.
130633176117714 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (130633176117713) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60144186814 + ... + 60144188985.
It is an arithmetic number, because the mean of its divisors is an integer number (16419363296700).
Almost surely, 2130633176117714 is an apocalyptic number.
130633176117714 is an abundant number, since it is smaller than the sum of its proper divisors (132076636629486).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130633176117714 is a wasteful number, since it uses less digits than its factorization.
130633176117714 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120288375985.
The product of its (nonzero) digits is 1333584, while the sum is 51.
The spelling of 130633176117714 in words is "one hundred thirty trillion, six hundred thirty-three billion, one hundred seventy-six million, one hundred seventeen thousand, seven hundred fourteen".
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