1310010301113 has 16 divisors (see below), whose sum is σ = 1757255852352. Its totient is φ = 868057560000.

The previous prime is 1310010301069. The next prime is 1310010301123. The reversal of 1310010301113 is 3111030100131.

It is not a de Polignac number, because 1310010301113 - 2⁶ = 1310010301049 is a prime.

It is a super-2 number, since 2×1310010301113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310010301092 and 1310010301101.

It is not an unprimeable number, because it can be changed into a prime (1310010301123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 397698 + ... + 1666788.

It is an arithmetic number, because the mean of its divisors is an integer number (109828490772).

Almost surely, 2^{1310010301113} is an apocalyptic number.

It is an amenable number.

1310010301113 is a deficient number, since it is larger than the sum of its proper divisors (447245551239).

1310010301113 is a wasteful number, since it uses less digits than its factorization.

1310010301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1271176.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 1310010301113 its reverse (3111030100131), we get a palindrome (4421040401244).

The spelling of 1310010301113 in words is "one trillion, three hundred ten billion, ten million, three hundred one thousand, one hundred thirteen".