Base | Representation |
---|---|
bin | 11101110010010100010100… |
… | …011011110100010111101011 |
3 | 122011211120211201011120200210 |
4 | 131302110110123310113223 |
5 | 114132310313411111021 |
6 | 1142341032033432203 |
7 | 36410343244133565 |
oct | 3562242433642753 |
9 | 564746751146623 |
10 | 131001140332011 |
11 | 388172a9585474 |
12 | 12838a94a0b663 |
13 | 581347bb833a1 |
14 | 244c6bbc42335 |
15 | 1022990eb0e76 |
hex | 7725146f45eb |
131001140332011 has 16 divisors (see below), whose sum is σ = 175740664538880. Its totient is φ = 86797860288480.
The previous prime is 131001140331989. The next prime is 131001140332061. The reversal of 131001140332011 is 110233041100131.
It is not a de Polignac number, because 131001140332011 - 213 = 131001140323819 is a prime.
It is a super-2 number, since 2×1310011403320112 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131001140332061) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116034901 + ... + 117158441.
It is an arithmetic number, because the mean of its divisors is an integer number (10983791533680).
Almost surely, 2131001140332011 is an apocalyptic number.
131001140332011 is a deficient number, since it is larger than the sum of its proper divisors (44739524206869).
131001140332011 is a wasteful number, since it uses less digits than its factorization.
131001140332011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1362146.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 131001140332011 its reverse (110233041100131), we get a palindrome (241234181432142).
The spelling of 131001140332011 in words is "one hundred thirty-one trillion, one billion, one hundred forty million, three hundred thirty-two thousand, eleven".
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