Base | Representation |
---|---|
bin | 1011111010100010001010… |
… | …1111011101111000101010 |
3 | 1201101100222202210122212020 |
4 | 2332220202233131320222 |
5 | 3204113234134340242 |
6 | 43510055232125310 |
7 | 2521313663153034 |
oct | 276504257357052 |
9 | 51340882718766 |
10 | 13100233121322 |
11 | 41a0861090346 |
12 | 1576ab5696836 |
13 | 74046787aa69 |
14 | 3340aa00ac54 |
15 | 17ab790be6ec |
hex | bea22bdde2a |
13100233121322 has 16 divisors (see below), whose sum is σ = 26445330414432. Its totient is φ = 4325933678480.
The previous prime is 13100233121317. The next prime is 13100233121359. The reversal of 13100233121322 is 22312133200131.
It is a super-2 number, since 2×131002331213222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100233121292 and 13100233121301.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10202673129 + ... + 10202674412.
It is an arithmetic number, because the mean of its divisors is an integer number (1652833150902).
Almost surely, 213100233121322 is an apocalyptic number.
13100233121322 is an abundant number, since it is smaller than the sum of its proper divisors (13345097293110).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100233121322 is a wasteful number, since it uses less digits than its factorization.
13100233121322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20405347653.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13100233121322 its reverse (22312133200131), we get a palindrome (35412366321453).
The spelling of 13100233121322 in words is "thirteen trillion, one hundred billion, two hundred thirty-three million, one hundred twenty-one thousand, three hundred twenty-two".
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