Base | Representation |
---|---|
bin | 1011111010100010001101… |
… | …1001001000010111000011 |
3 | 1201101101000112100112212100 |
4 | 2332220203121020113003 |
5 | 3204113244433340303 |
6 | 43510100302201443 |
7 | 2521314155042202 |
oct | 276504331102703 |
9 | 51341015315770 |
10 | 13100244043203 |
11 | 41a0867270099 |
12 | 1576ab9283283 |
13 | 740469c03105 |
14 | 3340ab651239 |
15 | 17ab7a02a8a3 |
hex | bea236485c3 |
13100244043203 has 96 divisors (see below), whose sum is σ = 19355241185280. Its totient is φ = 8537061173760.
The previous prime is 13100244043199. The next prime is 13100244043321. The reversal of 13100244043203 is 30234044200131.
13100244043203 is a `hidden beast` number, since 1 + 3 + 10 + 0 + 2 + 440 + 4 + 3 + 203 = 666.
It is not a de Polignac number, because 13100244043203 - 22 = 13100244043199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13100244043703) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 17631552850 + ... + 17631553592.
It is an arithmetic number, because the mean of its divisors is an integer number (201617095680).
Almost surely, 213100244043203 is an apocalyptic number.
13100244043203 is a deficient number, since it is larger than the sum of its proper divisors (6254997142077).
13100244043203 is a wasteful number, since it uses less digits than its factorization.
13100244043203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1689 (or 1686 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 13100244043203 its reverse (30234044200131), we get a palindrome (43334288243334).
The spelling of 13100244043203 in words is "thirteen trillion, one hundred billion, two hundred forty-four million, forty-three thousand, two hundred three".
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