Base | Representation |
---|---|
bin | 100111000010101… |
… | …1010000000110010 |
3 | 10101022001221012020 |
4 | 1032011122000302 |
5 | 10140332240424 |
6 | 333554412310 |
7 | 44315104635 |
oct | 11605320062 |
9 | 3338057166 |
10 | 1310040114 |
11 | 612535589 |
12 | 306891096 |
13 | 17b541b86 |
14 | c5db5c1c |
15 | 7a025079 |
hex | 4e15a032 |
1310040114 has 16 divisors (see below), whose sum is σ = 2669516352. Its totient is φ = 428440688.
The previous prime is 1310040103. The next prime is 1310040143. The reversal of 1310040114 is 4110400131.
It is a junction number, because it is equal to n+sod(n) for n = 1310040093 and 1310040102.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2059494 + ... + 2060129.
It is an arithmetic number, because the mean of its divisors is an integer number (166844772).
Almost surely, 21310040114 is an apocalyptic number.
1310040114 is an abundant number, since it is smaller than the sum of its proper divisors (1359476238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310040114 is a wasteful number, since it uses less digits than its factorization.
1310040114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4119681.
The product of its (nonzero) digits is 48, while the sum is 15.
The square root of 1310040114 is about 36194.4762912796. The cubic root of 1310040114 is about 1094.1953497239.
Adding to 1310040114 its reverse (4110400131), we get a palindrome (5420440245).
The spelling of 1310040114 in words is "one billion, three hundred ten million, forty thousand, one hundred fourteen".
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