Base | Representation |
---|---|
bin | 1011111010100010111000… |
… | …0000000110001111110011 |
3 | 1201101101110221021020021220 |
4 | 2332220232000012033303 |
5 | 3204114131014432243 |
6 | 43510130101120123 |
7 | 2521321445645115 |
oct | 276505600061763 |
9 | 51341427236256 |
10 | 13100422030323 |
11 | 41a0948788491 |
12 | 1576b489b9043 |
13 | 740497a50a34 |
14 | 3340c71433b5 |
15 | 17ab8a987783 |
hex | bea2e0063f3 |
13100422030323 has 16 divisors (see below), whose sum is σ = 17991015025920. Its totient is φ = 8473082344416.
The previous prime is 13100422030207. The next prime is 13100422030331. The reversal of 13100422030323 is 32303022400131.
13100422030323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13100422030323 - 213 = 13100422022131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13100422030293 and 13100422030302.
It is not an unprimeable number, because it can be changed into a prime (13100422030123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 170021743 + ... + 170098776.
It is an arithmetic number, because the mean of its divisors is an integer number (1124438439120).
Almost surely, 213100422030323 is an apocalyptic number.
13100422030323 is a deficient number, since it is larger than the sum of its proper divisors (4890592995597).
13100422030323 is a wasteful number, since it uses less digits than its factorization.
13100422030323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 340120906.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 13100422030323 its reverse (32303022400131), we get a palindrome (45403444430454).
The spelling of 13100422030323 in words is "thirteen trillion, one hundred billion, four hundred twenty-two million, thirty thousand, three hundred twenty-three".
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