Base | Representation |
---|---|
bin | 111101000000111111… |
… | …1111010011011000010 |
3 | 110112012201010101210110 |
4 | 1322001333322123002 |
5 | 4121322142042424 |
6 | 140105552212150 |
7 | 12316021625160 |
oct | 1720177723302 |
9 | 415181111713 |
10 | 131030034114 |
11 | 5062a046aa1 |
12 | 2148983a056 |
13 | c4823c9385 |
14 | 64b01d4230 |
15 | 361d4c8c29 |
hex | 1e81ffa6c2 |
131030034114 has 32 divisors (see below), whose sum is σ = 309158424576. Its totient is φ = 36229502160.
The previous prime is 131030034061. The next prime is 131030034119. The reversal of 131030034114 is 411430030131.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (131030034119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50317452 + ... + 50320055.
It is an arithmetic number, because the mean of its divisors is an integer number (9661200768).
Almost surely, 2131030034114 is an apocalyptic number.
131030034114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
131030034114 is an abundant number, since it is smaller than the sum of its proper divisors (178128390462).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131030034114 is a wasteful number, since it uses less digits than its factorization.
131030034114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100637550.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 131030034114 its reverse (411430030131), we get a palindrome (542460064245).
The spelling of 131030034114 in words is "one hundred thirty-one billion, thirty million, thirty-four thousand, one hundred fourteen".
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