Base | Representation |
---|---|
bin | 11000011010000111… |
… | …11000011110001001 |
3 | 1020211020112100210020 |
4 | 30031003320132021 |
5 | 203314112222213 |
6 | 10004144411053 |
7 | 642505234644 |
oct | 141503703611 |
9 | 36736470706 |
10 | 13104023433 |
11 | 5614974836 |
12 | 2658616a89 |
13 | 130aac3927 |
14 | 8c44c6a5b |
15 | 51a64d923 |
hex | 30d0f8789 |
13104023433 has 16 divisors (see below), whose sum is σ = 18494857920. Its totient is φ = 8238613824.
The previous prime is 13104023431. The next prime is 13104023441. The reversal of 13104023433 is 33432040131.
It is not a de Polignac number, because 13104023433 - 21 = 13104023431 is a prime.
It is a super-2 number, since 2×131040234332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13104023431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1747666 + ... + 1755147.
It is an arithmetic number, because the mean of its divisors is an integer number (1155928620).
Almost surely, 213104023433 is an apocalyptic number.
It is an amenable number.
13104023433 is a deficient number, since it is larger than the sum of its proper divisors (5390834487).
13104023433 is a wasteful number, since it uses less digits than its factorization.
13104023433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3502888.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 13104023433 its reverse (33432040131), we get a palindrome (46536063564).
The spelling of 13104023433 in words is "thirteen billion, one hundred four million, twenty-three thousand, four hundred thirty-three".
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