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13104023433 = 329433502813
BaseRepresentation
bin11000011010000111…
…11000011110001001
31020211020112100210020
430031003320132021
5203314112222213
610004144411053
7642505234644
oct141503703611
936736470706
1013104023433
115614974836
122658616a89
13130aac3927
148c44c6a5b
1551a64d923
hex30d0f8789

13104023433 has 16 divisors (see below), whose sum is σ = 18494857920. Its totient is φ = 8238613824.

The previous prime is 13104023431. The next prime is 13104023441. The reversal of 13104023433 is 33432040131.

It is not a de Polignac number, because 13104023433 - 21 = 13104023431 is a prime.

It is a super-2 number, since 2×131040234332 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13104023431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1747666 + ... + 1755147.

It is an arithmetic number, because the mean of its divisors is an integer number (1155928620).

Almost surely, 213104023433 is an apocalyptic number.

It is an amenable number.

13104023433 is a deficient number, since it is larger than the sum of its proper divisors (5390834487).

13104023433 is a wasteful number, since it uses less digits than its factorization.

13104023433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3502888.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 13104023433 its reverse (33432040131), we get a palindrome (46536063564).

The spelling of 13104023433 in words is "thirteen billion, one hundred four million, twenty-three thousand, four hundred thirty-three".

Divisors: 1 3 29 43 87 129 1247 3741 3502813 10508439 101581577 150620959 304744731 451862877 4368007811 13104023433