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13105403211434 = 2211102130416707
BaseRepresentation
bin1011111010110101011011…
…1001110010111010101010
31201101212100002020110012012
42332231112321302322222
53204204331210231214
643512312241115522
72521556052203042
oct276552671627252
951355302213165
1013105403211434
1141a2a74501596
121577ab9028ba2
13740aaca20991
1433443a906722
1517ad7ce2303e
hexbeb56e72eaa

13105403211434 has 16 divisors (see below), whose sum is σ = 19770616866336. Its totient is φ = 6515258425200.

The previous prime is 13105403211413. The next prime is 13105403211463. The reversal of 13105403211434 is 43411230450131.

It is a super-3 number, since 3×131054032114343 (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13105403211434.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14777492 + ... + 15639215.

It is an arithmetic number, because the mean of its divisors is an integer number (1235663554146).

Almost surely, 213105403211434 is an apocalyptic number.

13105403211434 is a deficient number, since it is larger than the sum of its proper divisors (6665213654902).

13105403211434 is a wasteful number, since it uses less digits than its factorization.

13105403211434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30417941.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 13105403211434 its reverse (43411230450131), we get a palindrome (56516633661565).

The spelling of 13105403211434 in words is "thirteen trillion, one hundred five billion, four hundred three million, two hundred eleven thousand, four hundred thirty-four".

Divisors: 1 2 211 422 1021 2042 215431 430862 30416707 60833414 6417925177 12835850354 31055457847 62110915694 6552701605717 13105403211434