Base | Representation |
---|---|
bin | 1011111010110101111010… |
… | …0011010101001111010001 |
3 | 1201101212200000201020111002 |
4 | 2332231132203111033101 |
5 | 3204210112033243213 |
6 | 43512333103431345 |
7 | 2521562201034053 |
oct | 276553643251721 |
9 | 51355600636432 |
10 | 13105531540433 |
11 | 41a302a992012 |
12 | 1577b33bb5555 |
13 | 740b004a29b7 |
14 | 33444d98d8d3 |
15 | 17ad89321658 |
hex | beb5e8d53d1 |
13105531540433 has 16 divisors (see below), whose sum is σ = 13365467660160. Its totient is φ = 12848003277696.
The previous prime is 13105531540421. The next prime is 13105531540469. The reversal of 13105531540433 is 33404513550131.
It is a cyclic number.
It is not a de Polignac number, because 13105531540433 - 28 = 13105531540177 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13105531540483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7231091 + ... + 8860007.
It is an arithmetic number, because the mean of its divisors is an integer number (835341728760).
Almost surely, 213105531540433 is an apocalyptic number.
It is an amenable number.
13105531540433 is a deficient number, since it is larger than the sum of its proper divisors (259936119727).
13105531540433 is a wasteful number, since it uses less digits than its factorization.
13105531540433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1629656.
The product of its (nonzero) digits is 162000, while the sum is 38.
The spelling of 13105531540433 in words is "thirteen trillion, one hundred five billion, five hundred thirty-one million, five hundred forty thousand, four hundred thirty-three".
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