Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0100011100110001000001 |
3 | 1201102100020102020202212001 |
4 | 2332302000310130301001 |
5 | 3204300100230422403 |
6 | 43514500230104001 |
7 | 2522123653240516 |
oct | 276620064346101 |
9 | 51370212222761 |
10 | 13110401420353 |
11 | 41a50a98a5966 |
12 | 1578a72aab001 |
13 | 7413c83a3253 |
14 | 33479265d30d |
15 | 17b071b23c1d |
hex | bec80d1cc41 |
13110401420353 has 16 divisors (see below), whose sum is σ = 13821378974080. Its totient is φ = 12401533569024.
The previous prime is 13110401420323. The next prime is 13110401420387. The reversal of 13110401420353 is 35302410401131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110401420353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110401420323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33608575 + ... + 33996427.
It is an arithmetic number, because the mean of its divisors is an integer number (863836185880).
Almost surely, 213110401420353 is an apocalyptic number.
It is an amenable number.
13110401420353 is a deficient number, since it is larger than the sum of its proper divisors (710977553727).
13110401420353 is a wasteful number, since it uses less digits than its factorization.
13110401420353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 390568.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13110401420353 its reverse (35302410401131), we get a palindrome (48412811821484).
The spelling of 13110401420353 in words is "thirteen trillion, one hundred ten billion, four hundred one million, four hundred twenty thousand, three hundred fifty-three".
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