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13110404021153 = 433312816332707
BaseRepresentation
bin1011111011001000000011…
…1110010111101110100001
31201102100020121010220110222
42332302000332113232201
53204300101412134103
643514500401532425
72522124014322155
oct276620076275641
951370217126428
1013110404021153
1141a510031198a
121578a73944115
137413c8aa3c9a
14334792b39065
1517b071e89638
hexbec80f97ba1

13110404021153 has 16 divisors (see below), whose sum is σ = 13456715940096. Its totient is φ = 12765979915920.

The previous prime is 13110404021137. The next prime is 13110404021159. The reversal of 13110404021153 is 35112040401131.

It is a cyclic number.

It is not a de Polignac number, because 13110404021153 - 24 = 13110404021137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13110404021159) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 400827626 + ... + 400860332.

It is an arithmetic number, because the mean of its divisors is an integer number (841044746256).

Almost surely, 213110404021153 is an apocalyptic number.

It is an amenable number.

13110404021153 is a deficient number, since it is larger than the sum of its proper divisors (346311918943).

13110404021153 is a wasteful number, since it uses less digits than its factorization.

13110404021153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61244.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 13110404021153 its reverse (35112040401131), we get a palindrome (48222444422284).

The spelling of 13110404021153 in words is "thirteen trillion, one hundred ten billion, four hundred four million, twenty-one thousand, one hundred fifty-three".

Divisors: 1 43 331 14233 28163 32707 1211009 1406401 9321953 10826017 400843979 465518731 921127241 39608471363 304893116771 13110404021153