Base | Representation |
---|---|
bin | 11101110011111010110111… |
… | …000000110001100010011011 |
3 | 122012020010000220002110202220 |
4 | 131303322313000301202123 |
5 | 114141111310440024011 |
6 | 1142503401220555123 |
7 | 36421321542616302 |
oct | 3563726700614233 |
9 | 565203026073686 |
10 | 131111242111131 |
11 | 38859a69121757 |
12 | 128562a1852aa3 |
13 | 5820977497809 |
14 | 2453b6475b439 |
15 | 1025786eb0506 |
hex | 773eb703189b |
131111242111131 has 16 divisors (see below), whose sum is σ = 174849869193984. Its totient is φ = 87390056322144.
The previous prime is 131111242111117. The next prime is 131111242111139.
131111242111131 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 131111242111131 - 230 = 131110168369307 is a prime.
It is a super-2 number, since 2×1311112421111312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131111242111139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 392773560 + ... + 393107226.
It is an arithmetic number, because the mean of its divisors is an integer number (10928116824624).
Almost surely, 2131111242111131 is an apocalyptic number.
131111242111131 is a deficient number, since it is larger than the sum of its proper divisors (43738627082853).
131111242111131 is a wasteful number, since it uses less digits than its factorization.
131111242111131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 359410.
The product of its digits is 144, while the sum is 24.
It can be divided in two parts, 131111 and 242111131, that added together give a palindrome (242242242).
The spelling of 131111242111131 in words is "one hundred thirty-one trillion, one hundred eleven billion, two hundred forty-two million, one hundred eleven thousand, one hundred thirty-one".
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