Base | Representation |
---|---|
bin | 11101110100000101110101… |
… | …101000000101101111010010 |
3 | 122012021020110102010110001220 |
4 | 131310011311220011233102 |
5 | 114141304431141214442 |
6 | 1142513031032505510 |
7 | 36422216630331534 |
oct | 3564056550055722 |
9 | 565236412113056 |
10 | 131123030023122 |
11 | 38863a68094485 |
12 | 1285863154b296 |
13 | 5821b05701c77 |
14 | 245456212b854 |
15 | 1025c26cd9eec |
hex | 774175a05bd2 |
131123030023122 has 64 divisors (see below), whose sum is σ = 264539435317248. Its totient is φ = 43327041912000.
The previous prime is 131123030023121. The next prime is 131123030023199. The reversal of 131123030023122 is 221320030321131.
It is a junction number, because it is equal to n+sod(n) for n = 131123030023092 and 131123030023101.
It is not an unprimeable number, because it can be changed into a prime (131123030023121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2189477463 + ... + 2189537349.
It is an arithmetic number, because the mean of its divisors is an integer number (4133428676832).
Almost surely, 2131123030023122 is an apocalyptic number.
131123030023122 is an abundant number, since it is smaller than the sum of its proper divisors (133416405294126).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131123030023122 is a wasteful number, since it uses less digits than its factorization.
131123030023122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66495.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 131123030023122 its reverse (221320030321131), we get a palindrome (352443060344253).
The spelling of 131123030023122 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, thirty million, twenty-three thousand, one hundred twenty-two".
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