Base | Representation |
---|---|
bin | 11101110101011000001010… |
… | …111100001001001001000010 |
3 | 122012120200122110121200100021 |
4 | 131311120022330021021002 |
5 | 114144232004203243132 |
6 | 1143021411214044054 |
7 | 36431466443364250 |
oct | 3565301274111102 |
9 | 565520573550307 |
10 | 131211434431042 |
11 | 38898503074629 |
12 | 128717a3aa962a |
13 | 582a253aa2904 |
14 | 245894b1615d0 |
15 | 102819d038997 |
hex | 77560af09242 |
131211434431042 has 32 divisors (see below), whose sum is σ = 230451432793344. Its totient is φ = 54854458848000.
The previous prime is 131211434431027. The next prime is 131211434431109. The reversal of 131211434431042 is 240134434112131.
131211434431042 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 131211434430989 and 131211434431007.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11328843 + ... + 19767790.
It is an arithmetic number, because the mean of its divisors is an integer number (7201607274792).
Almost surely, 2131211434431042 is an apocalyptic number.
131211434431042 is a deficient number, since it is larger than the sum of its proper divisors (99239998362302).
131211434431042 is a wasteful number, since it uses less digits than its factorization.
131211434431042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31104034.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 131211434431042 its reverse (240134434112131), we get a palindrome (371345868543173).
The spelling of 131211434431042 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred thirty-four million, four hundred thirty-one thousand, forty-two".
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