Base | Representation |
---|---|
bin | 11101110101100001011000… |
… | …011010011001110111110001 |
3 | 122012121122011200212011020120 |
4 | 131311201120122121313301 |
5 | 114144412232440102423 |
6 | 1143030124421000453 |
7 | 36432266511511050 |
oct | 3565413032316761 |
9 | 565548150764216 |
10 | 131221324144113 |
11 | 388a1718601415 |
12 | 128736a3b53129 |
13 | 582b16b987238 |
14 | 24592087b6397 |
15 | 102857b3adee3 |
hex | 775858699df1 |
131221324144113 has 16 divisors (see below), whose sum is σ = 199959076281216. Its totient is φ = 74982573987840.
The previous prime is 131221324144067. The next prime is 131221324144171. The reversal of 131221324144113 is 311441423122131.
It is not a de Polignac number, because 131221324144113 - 26 = 131221324144049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131221324144013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41773648 + ... + 44804913.
It is an arithmetic number, because the mean of its divisors is an integer number (12497442267576).
Almost surely, 2131221324144113 is an apocalyptic number.
It is an amenable number.
131221324144113 is a deficient number, since it is larger than the sum of its proper divisors (68737752137103).
131221324144113 is an equidigital number, since it uses as much as digits as its factorization.
131221324144113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86650744.
The product of its digits is 13824, while the sum is 33.
Adding to 131221324144113 its reverse (311441423122131), we get a palindrome (442662747266244).
The spelling of 131221324144113 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, three hundred twenty-four million, one hundred forty-four thousand, one hundred thirteen".
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