Base | Representation |
---|---|
bin | 11101110101100010111110… |
… | …010010000110100110001001 |
3 | 122012121210120210211102120220 |
4 | 131311202332102012212021 |
5 | 114144424233002302131 |
6 | 1143031010152540253 |
7 | 36432360043563504 |
oct | 3565427622064611 |
9 | 565553523742526 |
10 | 131223033244041 |
11 | 388a241531a4a2 |
12 | 12873aa03b1689 |
13 | 582b381a9b77b |
14 | 245932b78a13b |
15 | 102862b45de96 |
hex | 7758be486989 |
131223033244041 has 16 divisors (see below), whose sum is σ = 181217746877760. Its totient is φ = 84362519541440.
The previous prime is 131223033244031. The next prime is 131223033244087. The reversal of 131223033244041 is 140442330322131.
It is a cyclic number.
It is not a de Polignac number, because 131223033244041 - 26 = 131223033243977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131223033243993 and 131223033244011.
It is not an unprimeable number, because it can be changed into a prime (131223033244031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 918510015 + ... + 918652868.
It is an arithmetic number, because the mean of its divisors is an integer number (11326109179860).
Almost surely, 2131223033244041 is an apocalyptic number.
It is an amenable number.
131223033244041 is a deficient number, since it is larger than the sum of its proper divisors (49994713633719).
131223033244041 is a wasteful number, since it uses less digits than its factorization.
131223033244041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1837163736.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 131223033244041 its reverse (140442330322131), we get a palindrome (271665363566172).
The spelling of 131223033244041 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, thirty-three million, two hundred forty-four thousand, forty-one".
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