Base | Representation |
---|---|
bin | 1011111011110100101111… |
… | …1111100100000001111011 |
3 | 1201110111012121202222000021 |
4 | 2332331023333210001323 |
5 | 3204444133402340011 |
6 | 43524203010151311 |
7 | 2523030206660161 |
oct | 276751377440173 |
9 | 51414177688007 |
10 | 13122400043131 |
11 | 41aa1a67a6835 |
12 | 157b261282537 |
13 | 74258b174c42 |
14 | 3351adddd231 |
15 | 17b5251c1471 |
hex | bef4bfe407b |
13122400043131 has 16 divisors (see below), whose sum is σ = 13900660992000. Its totient is φ = 12352931383968.
The previous prime is 13122400043033. The next prime is 13122400043143. The reversal of 13122400043131 is 13134000422131.
It is a cyclic number.
It is not a de Polignac number, because 13122400043131 - 223 = 13122391654523 is a prime.
It is a super-2 number, since 2×131224000431312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13122400043096 and 13122400043105.
It is not an unprimeable number, because it can be changed into a prime (13122400143131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14669670 + ... + 15538468.
It is an arithmetic number, because the mean of its divisors is an integer number (868791312000).
Almost surely, 213122400043131 is an apocalyptic number.
13122400043131 is a deficient number, since it is larger than the sum of its proper divisors (778260948869).
13122400043131 is a wasteful number, since it uses less digits than its factorization.
13122400043131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 873858.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13122400043131 its reverse (13134000422131), we get a palindrome (26256400465262).
The spelling of 13122400043131 in words is "thirteen trillion, one hundred twenty-two billion, four hundred million, forty-three thousand, one hundred thirty-one".
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