1312704011808 has 720 divisors, whose sum is σ = 4741244988480. Its totient is φ = 354271325184.

The previous prime is 1312704011771. The next prime is 1312704011809. The reversal of 1312704011808 is 8081104072131.

1312704011808 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 70 + 401 + 180 + 8 = 666.

It is a super-3 number, since 3×1312704011808³ (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is not an unprimeable number, because it can be changed into a prime (1312704011809) by changing a digit.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 1175204466 + ... + 1175205582.

It is an arithmetic number, because the mean of its divisors is an integer number (6585062484).

Almost surely, 2^{1312704011808} is an apocalyptic number.

1312704011808 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312704011808, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2370622494240).

1312704011808 is an abundant number, since it is smaller than the sum of its proper divisors (3428540976672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312704011808 is a wasteful number, since it uses less digits than its factorization.

1312704011808 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1659 (or 1635 counting only the distinct ones).

The product of its (nonzero) digits is 10752, while the sum is 36.

Adding to 1312704011808 its reverse (8081104072131), we get a palindrome (9393808083939).

The spelling of 1312704011808 in words is "one trillion, three hundred twelve billion, seven hundred four million, eleven thousand, eight hundred eight".