Base | Representation |
---|---|
bin | 1011111100010010001110… |
… | …0010010001010011111001 |
3 | 1201111020121222000220002020 |
4 | 2333010203202101103321 |
5 | 3210111334132211413 |
6 | 43531552014025053 |
7 | 2523430231535250 |
oct | 277044342212371 |
9 | 51436558026066 |
10 | 13130311210233 |
11 | 420259640a768 |
12 | 15808aa7a8189 |
13 | 74324c1843c9 |
14 | 335720981797 |
15 | 17b8399c0c23 |
hex | bf1238914f9 |
13130311210233 has 16 divisors (see below), whose sum is σ = 20698027524480. Its totient is φ = 7244309632896.
The previous prime is 13130311210217. The next prime is 13130311210241. The reversal of 13130311210233 is 33201211303131.
13130311210233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13130311210233 - 24 = 13130311210217 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13130311210733) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10780222060 + ... + 10780223277.
It is an arithmetic number, because the mean of its divisors is an integer number (1293626720280).
Almost surely, 213130311210233 is an apocalyptic number.
It is an amenable number.
13130311210233 is a deficient number, since it is larger than the sum of its proper divisors (7567716314247).
13130311210233 is a wasteful number, since it uses less digits than its factorization.
13130311210233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21560445376.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 13130311210233 its reverse (33201211303131), we get a palindrome (46331522513364).
The spelling of 13130311210233 in words is "thirteen trillion, one hundred thirty billion, three hundred eleven million, two hundred ten thousand, two hundred thirty-three".
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