13131041110113 has 32 divisors (see below), whose sum is σ = 17763221237760. Its totient is φ = 8626655122560.

The previous prime is 13131041110097. The next prime is 13131041110127. The reversal of 13131041110113 is 31101114013131.

13131041110113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13131041110113 - 2⁴ = 13131041110097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13131041110113.

It is not an unprimeable number, because it can be changed into a prime (13131041110183) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1983837318 + ... + 1983843936.

It is an arithmetic number, because the mean of its divisors is an integer number (555100663680).

Almost surely, 2^{13131041110113} is an apocalyptic number.

It is an amenable number.

13131041110113 is a deficient number, since it is larger than the sum of its proper divisors (4632180127647).

13131041110113 is a wasteful number, since it uses less digits than its factorization.

13131041110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13149.

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 13131041110113 its reverse (31101114013131), we get a palindrome (44232155123244).

The spelling of 13131041110113 in words is "thirteen trillion, one hundred thirty-one billion, forty-one million, one hundred ten thousand, one hundred thirteen".