Base | Representation |
---|---|
bin | 10011000110111101011… |
… | …000111001000110010001 |
3 | 11122112110011011210201101 |
4 | 103012331120321012101 |
5 | 133003303431210213 |
6 | 2443125503504401 |
7 | 163604615420041 |
oct | 23067530710621 |
9 | 4575404153641 |
10 | 1313142444433 |
11 | 46699a749216 |
12 | 1925b48b8101 |
13 | 96aa0b50c91 |
14 | 477b0bd3721 |
15 | 24257b12bdd |
hex | 131bd639191 |
1313142444433 has 16 divisors (see below), whose sum is σ = 1320738693120. Its totient is φ = 1305574834176.
The previous prime is 1313142444391. The next prime is 1313142444437. The reversal of 1313142444433 is 3344442413131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313142444433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1313142444392 and 1313142444401.
It is not an unprimeable number, because it can be changed into a prime (1313142444437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 169938216 + ... + 169945942.
It is an arithmetic number, because the mean of its divisors is an integer number (82546168320).
Almost surely, 21313142444433 is an apocalyptic number.
It is an amenable number.
1313142444433 is a deficient number, since it is larger than the sum of its proper divisors (7596248687).
1313142444433 is an equidigital number, since it uses as much as digits as its factorization.
1313142444433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9456.
The product of its digits is 165888, while the sum is 37.
Adding to 1313142444433 its reverse (3344442413131), we get a palindrome (4657584857564).
The spelling of 1313142444433 in words is "one trillion, three hundred thirteen billion, one hundred forty-two million, four hundred forty-four thousand, four hundred thirty-three".
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