Base | Representation |
---|---|
bin | 11101110111000110111111… |
… | …001011001111100010000011 |
3 | 122020000001202221111001110000 |
4 | 131313012333023033202003 |
5 | 114203204201113432001 |
6 | 1143152210235211043 |
7 | 36443211203441166 |
oct | 3567067713174203 |
9 | 566001687431400 |
10 | 131330422405251 |
11 | 38933a127417a3 |
12 | 128908708a6a83 |
13 | 58385373cc144 |
14 | 24605d7d09add |
15 | 102b314234a86 |
hex | 7771bf2cf883 |
131330422405251 has 40 divisors (see below), whose sum is σ = 197161446482000. Its totient is φ = 87118865390592.
The previous prime is 131330422405219. The next prime is 131330422405253. The reversal of 131330422405251 is 152504224033131.
131330422405251 is a `hidden beast` number, since 1 + 3 + 1 + 330 + 4 + 224 + 0 + 52 + 51 = 666.
It is not a de Polignac number, because 131330422405251 - 25 = 131330422405219 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131330422405253) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 8800395 + ... + 18442011.
It is an arithmetic number, because the mean of its divisors is an integer number (4929036162050).
Almost surely, 2131330422405251 is an apocalyptic number.
131330422405251 is a deficient number, since it is larger than the sum of its proper divisors (65831024076749).
131330422405251 is an equidigital number, since it uses as much as digits as its factorization.
131330422405251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9642465 (or 9642456 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 131330422405251 its reverse (152504224033131), we get a palindrome (283834646438382).
The spelling of 131330422405251 in words is "one hundred thirty-one trillion, three hundred thirty billion, four hundred twenty-two million, four hundred five thousand, two hundred fifty-one".
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