Base | Representation |
---|---|
bin | 11101110111010011000110… |
… | …101000000101110100011001 |
3 | 122020001022100121220200201120 |
4 | 131313103012220011310121 |
5 | 114203412322132410131 |
6 | 1143202201222435453 |
7 | 36444151460010600 |
oct | 3567230650056431 |
9 | 566038317820646 |
10 | 131343432310041 |
11 | 38939489471826 |
12 | 128932a1892b89 |
13 | 583982b85b263 |
14 | 24610adad2a37 |
15 | 102b826491496 |
hex | 7774c6a05d19 |
131343432310041 has 48 divisors (see below), whose sum is σ = 204943289765760. Its totient is φ = 74601388350720.
The previous prime is 131343432310033. The next prime is 131343432310043. The reversal of 131343432310041 is 140013234343131.
It is not a de Polignac number, because 131343432310041 - 23 = 131343432310033 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 131343432309984 and 131343432310011.
It is not an unprimeable number, because it can be changed into a prime (131343432310043) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 880473501 + ... + 880622661.
It is an arithmetic number, because the mean of its divisors is an integer number (4269651870120).
Almost surely, 2131343432310041 is an apocalyptic number.
It is an amenable number.
131343432310041 is a deficient number, since it is larger than the sum of its proper divisors (73599857455719).
131343432310041 is a wasteful number, since it uses less digits than its factorization.
131343432310041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 185214 (or 185207 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 131343432310041 its reverse (140013234343131), we get a palindrome (271356666653172).
The spelling of 131343432310041 in words is "one hundred thirty-one trillion, three hundred forty-three billion, four hundred thirty-two million, three hundred ten thousand, forty-one".
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