Base | Representation |
---|---|
bin | 11101110111010011101000… |
… | …101110100100000010001011 |
3 | 122020001100211111110111112011 |
4 | 131313103220232210002023 |
5 | 114203420010113311021 |
6 | 1143202334101200351 |
7 | 36444201604656640 |
oct | 3567235056440213 |
9 | 566040744414464 |
10 | 131344004432011 |
11 | 389397524094a8 |
12 | 128934214000b7 |
13 | 58398c0245977 |
14 | 2461125a9ddc7 |
15 | 102b85b803de1 |
hex | 7774e8ba408b |
131344004432011 has 16 divisors (see below), whose sum is σ = 153615855343104. Its totient is φ = 109949857282944.
The previous prime is 131344004431949. The next prime is 131344004432077. The reversal of 131344004432011 is 110234400443131.
It is not a de Polignac number, because 131344004432011 - 217 = 131344004300939 is a prime.
It is a super-3 number, since 3×1313440044320113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (131344004432611) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22291591 + ... + 27560896.
It is an arithmetic number, because the mean of its divisors is an integer number (9600990958944).
Almost surely, 2131344004432011 is an apocalyptic number.
131344004432011 is a deficient number, since it is larger than the sum of its proper divisors (22271850911093).
131344004432011 is an equidigital number, since it uses as much as digits as its factorization.
131344004432011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49861290.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131344004432011 its reverse (110234400443131), we get a palindrome (241578404875142).
The spelling of 131344004432011 in words is "one hundred thirty-one trillion, three hundred forty-four billion, four million, four hundred thirty-two thousand, eleven".
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