Search a number
-
+
131403434154554 = 2163666160513139
BaseRepresentation
bin11101111000001010111111…
…000000111101101000111010
3122020021001020020222012200002
4131320022333000331220322
5114210403213120421204
61143245523154313002
736451404411200102
oct3570127700755072
9566231206865602
10131403434154554
1138961979999681
12128a2a48288762
1358423a17b2b73
142463d62906202
15102d188e5a91e
hex7782bf03da3a

131403434154554 has 16 divisors (see below), whose sum is σ = 198344161030560. Its totient is φ = 65288834850960.

The previous prime is 131403434154523. The next prime is 131403434154571. The reversal of 131403434154554 is 455451434304131.

It is a super-2 number, since 2×1314034341545542 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131403434154499 and 131403434154508.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28085084 + ... + 32428055.

It is an arithmetic number, because the mean of its divisors is an integer number (12396510064410).

Almost surely, 2131403434154554 is an apocalyptic number.

131403434154554 is a deficient number, since it is larger than the sum of its proper divisors (66940726876006).

131403434154554 is a wasteful number, since it uses less digits than its factorization.

131403434154554 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60519965.

The product of its (nonzero) digits is 3456000, while the sum is 47.

Adding to 131403434154554 its reverse (455451434304131), we get a palindrome (586854868458685).

The spelling of 131403434154554 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-four million, one hundred fifty-four thousand, five hundred fifty-four".

Divisors: 1 2 163 326 6661 13322 1085743 2171486 60513139 121026278 9863641657 19727283314 403078018879 806156037758 65701717077277 131403434154554