Base | Representation |
---|---|
bin | 11000011111100110… |
… | …01001101011110010 |
3 | 1020221102222122110000 |
4 | 30033303021223302 |
5 | 203412343003023 |
6 | 10012505250430 |
7 | 643603615305 |
oct | 141763115362 |
9 | 36842878400 |
10 | 13149969138 |
11 | 56388a6499 |
12 | 266ba93a16 |
13 | 131748c837 |
14 | 8ca646b3c |
15 | 51e6c7243 |
hex | 30fcc9af2 |
13149969138 has 20 divisors (see below), whose sum is σ = 29465671950. Its totient is φ = 4383322992.
The previous prime is 13149969137. The next prime is 13149969167. The reversal of 13149969138 is 83196994131.
13149969138 is a `hidden beast` number, since 1 + 31 + 499 + 6 + 91 + 38 = 666.
It can be written as a sum of positive squares in only one way, i.e., 13037757489 + 112211649 = 114183^2 + 10593^2 .
It is a Harshad number since it is a multiple of its sum of digits (54).
It is not an unprimeable number, because it can be changed into a prime (13149969137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 40586163 + ... + 40586486.
Almost surely, 213149969138 is an apocalyptic number.
13149969138 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
13149969138 is an abundant number, since it is smaller than the sum of its proper divisors (16315702812).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13149969138 is an equidigital number, since it uses as much as digits as its factorization.
13149969138 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81172663 (or 81172654 counting only the distinct ones).
The product of its digits is 1259712, while the sum is 54.
The spelling of 13149969138 in words is "thirteen billion, one hundred forty-nine million, nine hundred sixty-nine thousand, one hundred thirty-eight".
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