Base | Representation |
---|---|
bin | 1011111101101000000011… |
… | …0001111011100110000010 |
3 | 1201120110002121101200101212 |
4 | 2333122000301323212002 |
5 | 3211001030202330104 |
6 | 43550322112330122 |
7 | 2525204166645341 |
oct | 277320061734602 |
9 | 51513077350355 |
10 | 13153350433154 |
11 | 4211339459968 |
12 | 158525a543942 |
13 | 7454813c74a9 |
14 | 3368a875db58 |
15 | 17c23747c36e |
hex | bf680c7b982 |
13153350433154 has 16 divisors (see below), whose sum is σ = 19871171201088. Its totient is φ = 6529692001872.
The previous prime is 13153350433141. The next prime is 13153350433163. The reversal of 13153350433154 is 45133405335131.
13153350433154 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15922022 + ... + 16727745.
It is an arithmetic number, because the mean of its divisors is an integer number (1241948200068).
Almost surely, 213153350433154 is an apocalyptic number.
13153350433154 is a deficient number, since it is larger than the sum of its proper divisors (6717820767934).
13153350433154 is a wasteful number, since it uses less digits than its factorization.
13153350433154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32651209.
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 13153350433154 its reverse (45133405335131), we get a palindrome (58286755768285).
The spelling of 13153350433154 in words is "thirteen trillion, one hundred fifty-three billion, three hundred fifty million, four hundred thirty-three thousand, one hundred fifty-four".
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