Base | Representation |
---|---|
bin | 1011111101101110100111… |
… | …0111001111010101010001 |
3 | 1201120121122110210022201021 |
4 | 2333123221313033111101 |
5 | 3211013133014314101 |
6 | 43551213051435441 |
7 | 2525265655126003 |
oct | 277335167172521 |
9 | 51517573708637 |
10 | 13155113432401 |
11 | 4212063641336 |
12 | 1585670a55b81 |
13 | 7456a2730c05 |
14 | 3369d4964373 |
15 | 17c2dc1275a1 |
hex | bf6e9dcf551 |
13155113432401 has 16 divisors (see below), whose sum is σ = 14054528238400. Its totient is φ = 12276412239168.
The previous prime is 13155113432341. The next prime is 13155113432429. The reversal of 13155113432401 is 10423431155131.
It is a cyclic number.
It is not a de Polignac number, because 13155113432401 - 223 = 13155105043793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13155113432491) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60094735 + ... + 60313243.
It is an arithmetic number, because the mean of its divisors is an integer number (878408014900).
Almost surely, 213155113432401 is an apocalyptic number.
It is an amenable number.
13155113432401 is a deficient number, since it is larger than the sum of its proper divisors (899414805999).
13155113432401 is a wasteful number, since it uses less digits than its factorization.
13155113432401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 265888.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 13155113432401 its reverse (10423431155131), we get a palindrome (23578544587532).
The spelling of 13155113432401 in words is "thirteen trillion, one hundred fifty-five billion, one hundred thirteen million, four hundred thirty-two thousand, four hundred one".
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