Base | Representation |
---|---|
bin | 1100000000011010110101… |
… | …0100111011011010111010 |
3 | 1201202000222020211111110001 |
4 | 3000012231110323122322 |
5 | 3212242322131221432 |
6 | 44024340223543214 |
7 | 2531523400220050 |
oct | 300065524733272 |
9 | 51660866744401 |
10 | 13201342445242 |
11 | 422a726719976 |
12 | 1592612a5ab0a |
13 | 749b5c154093 |
14 | 338d3c5161d0 |
15 | 17d5e58d29e7 |
hex | c01ad53b6ba |
13201342445242 has 64 divisors (see below), whose sum is σ = 24217008940800. Its totient is φ = 5271092858880.
The previous prime is 13201342445233. The next prime is 13201342445273. The reversal of 13201342445242 is 24254424310231.
13201342445242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×132013424452423 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90289548 + ... + 90435640.
It is an arithmetic number, because the mean of its divisors is an integer number (378390764700).
Almost surely, 213201342445242 is an apocalyptic number.
13201342445242 is a deficient number, since it is larger than the sum of its proper divisors (11015666495558).
13201342445242 is a wasteful number, since it uses less digits than its factorization.
13201342445242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151751.
The product of its (nonzero) digits is 184320, while the sum is 37.
Adding to 13201342445242 its reverse (24254424310231), we get a palindrome (37455766755473).
The spelling of 13201342445242 in words is "thirteen trillion, two hundred one billion, three hundred forty-two million, four hundred forty-five thousand, two hundred forty-two".
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