Base | Representation |
---|---|
bin | 11110000001001010010100… |
… | …111011010101000111011011 |
3 | 122022110002210122122200010011 |
4 | 132001022110323111013123 |
5 | 114301013411022403103 |
6 | 1144441411543502351 |
7 | 36544134330412000 |
oct | 3601122473250733 |
9 | 568402718580104 |
10 | 132021203325403 |
11 | 3907a972545237 |
12 | 12982715a579b7 |
13 | 58887138b1142 |
14 | 2485c08a8b8a7 |
15 | 103e293c87d6d |
hex | 781294ed51db |
132021203325403 has 32 divisors (see below), whose sum is σ = 155723002416000. Its totient is φ = 111866187299328.
The previous prime is 132021203325383. The next prime is 132021203325409. The reversal of 132021203325403 is 304523302120231.
It is not a de Polignac number, because 132021203325403 - 25 = 132021203325371 is a prime.
It is a super-2 number, since 2×1320212033254032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132021203325409) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 146477175 + ... + 147375727.
It is an arithmetic number, because the mean of its divisors is an integer number (4866343825500).
Almost surely, 2132021203325403 is an apocalyptic number.
132021203325403 is a deficient number, since it is larger than the sum of its proper divisors (23701799090597).
132021203325403 is an frugal number, since it uses more digits than its factorization.
132021203325403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 903476 (or 903462 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 132021203325403 its reverse (304523302120231), we get a palindrome (436544505445634).
The spelling of 132021203325403 in words is "one hundred thirty-two trillion, twenty-one billion, two hundred three million, three hundred twenty-five thousand, four hundred three".
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