Base | Representation |
---|---|
bin | 11110000001011100001000… |
… | …101011111111010001111010 |
3 | 122022111221011022002011011012 |
4 | 132001130020223333101322 |
5 | 114301322041241030132 |
6 | 1144454253230433522 |
7 | 36545412231645443 |
oct | 3601341053772172 |
9 | 568457138064135 |
10 | 132040325330042 |
11 | 39087a95401358 |
12 | 129863719628a2 |
13 | 588a4703c809c |
14 | 2486b005042ca |
15 | 103ea128c20b2 |
hex | 781708aff47a |
132040325330042 has 16 divisors (see below), whose sum is σ = 198081382625280. Its totient is φ = 66013198128528.
The previous prime is 132040325330041. The next prime is 132040325330059. The reversal of 132040325330042 is 240033523040231.
It is a super-3 number, since 3×1320403253300423 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132040325329990 and 132040325330008.
It is not an unprimeable number, because it can be changed into a prime (132040325330041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1156193288 + ... + 1156307484.
It is an arithmetic number, because the mean of its divisors is an integer number (12380086414080).
Almost surely, 2132040325330042 is an apocalyptic number.
132040325330042 is a deficient number, since it is larger than the sum of its proper divisors (66041057295238).
132040325330042 is a wasteful number, since it uses less digits than its factorization.
132040325330042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170125.
The product of its (nonzero) digits is 51840, while the sum is 32.
Adding to 132040325330042 its reverse (240033523040231), we get a palindrome (372073848370273).
The spelling of 132040325330042 in words is "one hundred thirty-two trillion, forty billion, three hundred twenty-five million, three hundred thirty thousand, forty-two".
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