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132040325330042 = 21368742239114197
BaseRepresentation
bin11110000001011100001000…
…101011111111010001111010
3122022111221011022002011011012
4132001130020223333101322
5114301322041241030132
61144454253230433522
736545412231645443
oct3601341053772172
9568457138064135
10132040325330042
1139087a95401358
12129863719628a2
13588a4703c809c
142486b005042ca
15103ea128c20b2
hex781708aff47a

132040325330042 has 16 divisors (see below), whose sum is σ = 198081382625280. Its totient is φ = 66013198128528.

The previous prime is 132040325330041. The next prime is 132040325330059. The reversal of 132040325330042 is 240033523040231.

It is a super-3 number, since 3×1320403253300423 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132040325329990 and 132040325330008.

It is not an unprimeable number, because it can be changed into a prime (132040325330041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1156193288 + ... + 1156307484.

It is an arithmetic number, because the mean of its divisors is an integer number (12380086414080).

Almost surely, 2132040325330042 is an apocalyptic number.

132040325330042 is a deficient number, since it is larger than the sum of its proper divisors (66041057295238).

132040325330042 is a wasteful number, since it uses less digits than its factorization.

132040325330042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170125.

The product of its (nonzero) digits is 51840, while the sum is 32.

Adding to 132040325330042 its reverse (240033523040231), we get a palindrome (372073848370273).

The spelling of 132040325330042 in words is "one hundred thirty-two trillion, forty billion, three hundred twenty-five million, three hundred thirty thousand, forty-two".

Divisors: 1 2 13687 27374 42239 84478 114197 228394 578125193 1156250386 1563014339 3126028678 4823567083 9647134166 66020162665021 132040325330042