Base | Representation |
---|---|
bin | 11110000001011110111001… |
… | …111111100100101000011001 |
3 | 122022112012211121111121201210 |
4 | 132001132321333210220121 |
5 | 114301344134301443001 |
6 | 1144455504332533333 |
7 | 36545546032332132 |
oct | 3601367177445031 |
9 | 568465747447653 |
10 | 132043300031001 |
11 | 390892815621a7 |
12 | 12986a62021249 |
13 | 588a825792278 |
14 | 2486d03602c89 |
15 | 103eb38b19dd6 |
hex | 7817b9fe4a19 |
132043300031001 has 16 divisors (see below), whose sum is σ = 176953571803008. Its totient is φ = 87580958304000.
The previous prime is 132043300030981. The next prime is 132043300031003. The reversal of 132043300031001 is 100130003340231.
It is a de Polignac number, because none of the positive numbers 2k-132043300031001 is a prime.
It is a super-2 number, since 2×1320433000310012 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132043300031003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49042636 + ... + 51664946.
It is an arithmetic number, because the mean of its divisors is an integer number (11059598237688).
Almost surely, 2132043300031001 is an apocalyptic number.
It is an amenable number.
132043300031001 is a deficient number, since it is larger than the sum of its proper divisors (44910271772007).
132043300031001 is a wasteful number, since it uses less digits than its factorization.
132043300031001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2707712.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 132043300031001 its reverse (100130003340231), we get a palindrome (232173303371232).
The spelling of 132043300031001 in words is "one hundred thirty-two trillion, forty-three billion, three hundred million, thirty-one thousand, one".
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