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13205522000153 = 721161363145703
BaseRepresentation
bin1100000000101010011001…
…1100101010100100011001
31201202102202112101212221002
43000022212130222210121
53212324402113001103
644030311050154345
72532032100646250
oct300124634524431
951672675355832
1013205522000153
1142314809a138a
12159339a7229b5
1374a377021bb2
14339217649797
1517d78c7c4488
hexc02a672a919

13205522000153 has 16 divisors (see below), whose sum is σ = 15163902514176. Its totient is φ = 11265113316240.

The previous prime is 13205522000137. The next prime is 13205522000161. The reversal of 13205522000153 is 35100022550231.

It is not a de Polignac number, because 13205522000153 - 24 = 13205522000137 is a prime.

It is a super-2 number, since 2×132055220001532 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13205522000173) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 90560300 + ... + 90706002.

It is an arithmetic number, because the mean of its divisors is an integer number (947743907136).

Almost surely, 213205522000153 is an apocalyptic number.

It is an amenable number.

13205522000153 is a deficient number, since it is larger than the sum of its proper divisors (1958380514023).

13205522000153 is a wasteful number, since it uses less digits than its factorization.

13205522000153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 207284.

The product of its (nonzero) digits is 9000, while the sum is 29.

Adding to 13205522000153 its reverse (35100022550231), we get a palindrome (48305544550384).

The spelling of 13205522000153 in words is "thirteen trillion, two hundred five billion, five hundred twenty-two million, one hundred fifty-three", and thus it is an aban number.

Divisors: 1 7 211 1477 61363 145703 429541 1019921 12947593 30743333 90633151 215203331 8940773189 62585412323 1886503142879 13205522000153