Base | Representation |
---|---|
bin | 11110000010110011011001… |
… | …011001001000111100010001 |
3 | 122022211220000010021110202202 |
4 | 132002303121121020330101 |
5 | 114304340433402441431 |
6 | 1145005310433052545 |
7 | 36555240136126031 |
oct | 3602633131107421 |
9 | 568756003243682 |
10 | 132134021140241 |
11 | 391137a623033a |
12 | 129a05603b7155 |
13 | 5896252b04bb3 |
14 | 248b46c1b18c1 |
15 | 10421984388cb |
hex | 782cd9648f11 |
132134021140241 has 16 divisors (see below), whose sum is σ = 136273570767360. Its totient is φ = 128071918141440.
The previous prime is 132134021140183. The next prime is 132134021140259. The reversal of 132134021140241 is 142041120431231.
It is a cyclic number.
It is not a de Polignac number, because 132134021140241 - 234 = 132116841271057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132134021140741) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49245680 + ... + 51859473.
It is an arithmetic number, because the mean of its divisors is an integer number (8517098172960).
Almost surely, 2132134021140241 is an apocalyptic number.
It is an amenable number.
132134021140241 is a deficient number, since it is larger than the sum of its proper divisors (4139549627119).
132134021140241 is a wasteful number, since it uses less digits than its factorization.
132134021140241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101105536.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 132134021140241 its reverse (142041120431231), we get a palindrome (274175141571472).
The spelling of 132134021140241 in words is "one hundred thirty-two trillion, one hundred thirty-four billion, twenty-one million, one hundred forty thousand, two hundred forty-one".
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