Base | Representation |
---|---|
bin | 1100000010001101111110… |
… | …1000111010001101011010 |
3 | 1201211222202100022202210022 |
4 | 3000203133220322031122 |
5 | 3213244122314040114 |
6 | 44050451244150442 |
7 | 2533666344246053 |
oct | 300433750721532 |
9 | 51758670282708 |
10 | 13232251315034 |
11 | 42418479a3264 |
12 | 15985ba238422 |
13 | 74ca468c9b4b |
14 | 33a63154972a |
15 | 17e3041db48e |
hex | c08dfa3a35a |
13232251315034 has 16 divisors (see below), whose sum is σ = 20924575865856. Its totient is φ = 6266474540400.
The previous prime is 13232251315009. The next prime is 13232251315039. The reversal of 13232251315034 is 43051315223231.
13232251315034 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13232251314985 and 13232251315003.
It is not an unprimeable number, because it can be changed into a prime (13232251315039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2270458877 + ... + 2270464704.
It is an arithmetic number, because the mean of its divisors is an integer number (1307785991616).
Almost surely, 213232251315034 is an apocalyptic number.
13232251315034 is a deficient number, since it is larger than the sum of its proper divisors (7692324550822).
13232251315034 is a wasteful number, since it uses less digits than its factorization.
13232251315034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4540923661.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 13232251315034 its reverse (43051315223231), we get a palindrome (56283566538265).
The spelling of 13232251315034 in words is "thirteen trillion, two hundred thirty-two billion, two hundred fifty-one million, three hundred fifteen thousand, thirty-four".
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