Base | Representation |
---|---|
bin | 11110000110110101101010… |
… | …111001100000110111100001 |
3 | 122100211101210222001212221102 |
4 | 132012311222321200313201 |
5 | 114323411411044330423 |
6 | 1145340532511404145 |
7 | 36614255306400110 |
oct | 3606655271406741 |
9 | 570741728055842 |
10 | 132411340230113 |
11 | 3921037467010a |
12 | 12a26255b23655 |
13 | 58b64499c7509 |
14 | 249aa58d67c77 |
15 | 10494c9817c28 |
hex | 786d6ae60de1 |
132411340230113 has 16 divisors (see below), whose sum is σ = 156645841248000. Its totient is φ = 109511508748992.
The previous prime is 132411340230097. The next prime is 132411340230121. The reversal of 132411340230113 is 311032043114231.
It is not a de Polignac number, because 132411340230113 - 24 = 132411340230097 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (132411340230173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 208879358 + ... + 209512311.
It is an arithmetic number, because the mean of its divisors is an integer number (9790365078000).
Almost surely, 2132411340230113 is an apocalyptic number.
It is an amenable number.
132411340230113 is a deficient number, since it is larger than the sum of its proper divisors (24234501017887).
132411340230113 is a wasteful number, since it uses less digits than its factorization.
132411340230113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 418393264.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 132411340230113 its reverse (311032043114231), we get a palindrome (443443383344344).
The spelling of 132411340230113 in words is "one hundred thirty-two trillion, four hundred eleven billion, three hundred forty million, two hundred thirty thousand, one hundred thirteen".
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