Base | Representation |
---|---|
bin | 11000101011100101… |
… | …10011011110001011 |
3 | 1021012110020020201111 |
4 | 30111302303132023 |
5 | 204114114311301 |
6 | 10030501031151 |
7 | 646234513120 |
oct | 142562633613 |
9 | 37173206644 |
10 | 13250541451 |
11 | 568a648a04 |
12 | 26996b54b7 |
13 | 1332273994 |
14 | 8d9b46747 |
15 | 528441551 |
hex | 315cb378b |
13250541451 has 16 divisors (see below), whose sum is σ = 15888252928. Its totient is φ = 10811037600.
The previous prime is 13250541449. The next prime is 13250541487. The reversal of 13250541451 is 15414505231.
It is a cyclic number.
It is not a de Polignac number, because 13250541451 - 21 = 13250541449 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is not an unprimeable number, because it can be changed into a prime (13250541751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 487275 + ... + 513748.
It is an arithmetic number, because the mean of its divisors is an integer number (993015808).
Almost surely, 213250541451 is an apocalyptic number.
13250541451 is a deficient number, since it is larger than the sum of its proper divisors (2637711477).
13250541451 is a wasteful number, since it uses less digits than its factorization.
13250541451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1001122.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 13250541451 in words is "thirteen billion, two hundred fifty million, five hundred forty-one thousand, four hundred fifty-one".
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