Base | Representation |
---|---|
bin | 11110001111100100010001… |
… | …111000110111101000100010 |
3 | 122102221202000012111120200011 |
4 | 132033210101320313220202 |
5 | 114413223304412413214 |
6 | 1150520250351515134 |
7 | 40005511050063613 |
oct | 3617442170675042 |
9 | 572852005446604 |
10 | 133011142310434 |
11 | 39421788271723 |
12 | 12b0254a528aaa |
13 | 592ab8764858b |
14 | 24bbab8c0bc0a |
15 | 1059dd20dcac4 |
hex | 78f911e37a22 |
133011142310434 has 16 divisors (see below), whose sum is σ = 206265259664640. Its totient is φ = 64262566655280.
The previous prime is 133011142310407. The next prime is 133011142310489. The reversal of 133011142310434 is 434013241110331.
133011142310434 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 133011142310396 and 133011142310405.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1627683729 + ... + 1627765444.
It is an arithmetic number, because the mean of its divisors is an integer number (12891578729040).
Almost surely, 2133011142310434 is an apocalyptic number.
133011142310434 is a deficient number, since it is larger than the sum of its proper divisors (73254117354206).
133011142310434 is a wasteful number, since it uses less digits than its factorization.
133011142310434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3255449865.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 133011142310434 its reverse (434013241110331), we get a palindrome (567024383420765).
The spelling of 133011142310434 in words is "one hundred thirty-three trillion, eleven billion, one hundred forty-two million, three hundred ten thousand, four hundred thirty-four".
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