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13301201022312 = 2337282119017247
BaseRepresentation
bin1100000110001110110101…
…0111001010110101101000
31202002120201120100210220110
43001203231113022311220
53220411324430203222
644142253135454320
72541660106140600
oct301435527126550
952076646323813
1013301201022312
11426900a240915
1215a9a413873a0
137563b45788c8
1433dad2881c00
15180edc4d430c
hexc18ed5cad68

13301201022312 has 192 divisors, whose sum is σ = 38754900023040. Its totient is φ = 3793194048000.

The previous prime is 13301201022283. The next prime is 13301201022313. The reversal of 13301201022312 is 21322010210331.

13301201022312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is not an unprimeable number, because it can be changed into a prime (13301201022313) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1835404273 + ... + 1835411519.

It is an arithmetic number, because the mean of its divisors is an integer number (201848437620).

Almost surely, 213301201022312 is an apocalyptic number.

13301201022312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13301201022312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19377450011520).

13301201022312 is an abundant number, since it is smaller than the sum of its proper divisors (25453699000728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13301201022312 is a wasteful number, since it uses less digits than its factorization.

13301201022312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9992 (or 9981 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13301201022312 its reverse (21322010210331), we get a palindrome (34623211232643).

The spelling of 13301201022312 in words is "thirteen trillion, three hundred one billion, two hundred one million, twenty-two thousand, three hundred twelve".