Base | Representation |
---|---|
bin | 11110010000010110110000… |
… | …000111000010011000011001 |
3 | 122110010220220002022012200110 |
4 | 132100112300013002120121 |
5 | 114420120302111312103 |
6 | 1151001212135554533 |
7 | 40012440040365516 |
oct | 3620266007023031 |
9 | 573126802265613 |
10 | 133065336432153 |
11 | 39442768456474 |
12 | 12b10b53b2ba49 |
13 | 59330132b6518 |
14 | 24c057a58430d |
15 | 105b504ca0403 |
hex | 7905b01c2619 |
133065336432153 has 32 divisors (see below), whose sum is σ = 189159052008960. Its totient is φ = 82967604894720.
The previous prime is 133065336432109. The next prime is 133065336432179. The reversal of 133065336432153 is 351234633560331.
It is not a de Polignac number, because 133065336432153 - 221 = 133065334335001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133065336432653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44725851 + ... + 47608112.
It is an arithmetic number, because the mean of its divisors is an integer number (5911220375280).
Almost surely, 2133065336432153 is an apocalyptic number.
It is an amenable number.
133065336432153 is a deficient number, since it is larger than the sum of its proper divisors (56093715576807).
133065336432153 is a wasteful number, since it uses less digits than its factorization.
133065336432153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 92334309.
The product of its (nonzero) digits is 5248800, while the sum is 48.
Adding to 133065336432153 its reverse (351234633560331), we get a palindrome (484299969992484).
The spelling of 133065336432153 in words is "one hundred thirty-three trillion, sixty-five billion, three hundred thirty-six million, four hundred thirty-two thousand, one hundred fifty-three".
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