Base | Representation |
---|---|
bin | 1100000111010110111011… |
… | …0011010111110001001001 |
3 | 1202011102200012200001000001 |
4 | 3001311232303113301021 |
5 | 3221220442422422403 |
6 | 44155213302043001 |
7 | 2543243465313244 |
oct | 301655663276111 |
9 | 52142605601001 |
10 | 13320552545353 |
11 | 427623a711569 |
12 | 15b1742119461 |
13 | 7581797b3861 |
14 | 340a0a9a225b |
15 | 181771358c1d |
hex | c1d6ecd7c49 |
13320552545353 has 16 divisors (see below), whose sum is σ = 13616816273280. Its totient is φ = 13026015044224.
The previous prime is 13320552545323. The next prime is 13320552545357. The reversal of 13320552545353 is 35354525502331.
It is a cyclic number.
It is not a de Polignac number, because 13320552545353 - 213 = 13320552537161 is a prime.
It is a super-2 number, since 2×133205525453532 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13320552545357) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22077828 + ... + 22673146.
It is an arithmetic number, because the mean of its divisors is an integer number (851051017080).
Almost surely, 213320552545353 is an apocalyptic number.
It is an amenable number.
13320552545353 is a deficient number, since it is larger than the sum of its proper divisors (296263727927).
13320552545353 is an equidigital number, since it uses as much as digits as its factorization.
13320552545353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 596768.
The product of its (nonzero) digits is 4050000, while the sum is 46.
The spelling of 13320552545353 in words is "thirteen trillion, three hundred twenty billion, five hundred fifty-two million, five hundred forty-five thousand, three hundred fifty-three".
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